3x^2(x-1)(x+1)-10x^2+4=0

Question

3x^2(x-1)(x+1)-10x^2+4=0

Answer 1

3x²(x-1)(x+1)-10x²+4=0
3x²(x²-1)-10x²+4=0
3x^4-3x²-10x²+4=0
3x^4-13x²+4=0  x²=t>0
3t²-13t+4=0
D=169-4*3*4=169-48=121
t1=(13-11)/6=2/6=1/3,    x²=1/3  x1=-√1/3,  x2=√1/3
t2=(13+11)/6=24/6=4,  x²=4  x3=-2    x4=2

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