(2400+z)/40=80,1500/x-300=200,2800-(t-357)=100

Question

(2400+z)/40=80,1500/x-300=200,2800-(t-357)=100

Answer 1

1)2400+Z=40*80

2400+z=3200

z=3200-2400

z=800

2)1500\x=200+300

1500\x=500

x=1500\500

x=3

3)-(t-357)=100-2800

-(t-357)=-2700

t-357=2700

t=2700+357

t=3057