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Решите задачу:

$\frac{108}{160} +( \frac{92}{160} - \frac{46}{160} )= \frac{108}{160} + \frac{92}{160} - \frac{46}{160} = \frac{154}{160} = \frac{77}{80} \\ \\ \frac{108}{160} - \frac{92}{160} + \frac{92}{160} = \frac{108}{160} = \frac{54}{80} = \frac{27}{40} \\ \\ ( \frac{38}{130} + \frac{79}{130} )- \frac{8}{130} = \frac{117}{130} - \frac{8}{130} = \frac{109}{130}$