0\\x-3>0\end{cases}\rightarrow x>3\\log_8(x-2)-log_8(x-3)>\frac{1}{3}\\log_8(\frac{x-2}{x-3})>\frac{1}{3};8>1\\\frac{x-2}{x-3}>2\\x-2>2x-6\\x<4\\OD3:............(3)/////////>x\\///////////////////(4)....>x\\x\in(3;4)" alt="OD3:\begin{cases}x-2>0\\x-3>0\end{cases}\rightarrow x>3\\log_8(x-2)-log_8(x-3)>\frac{1}{3}\\log_8(\frac{x-2}{x-3})>\frac{1}{3};8>1\\\frac{x-2}{x-3}>2\\x-2>2x-6\\x<4\\OD3:............(3)/////////>x\\///////////////////(4)....>x\\x\in(3;4)" align="absmiddle" class="latex-formula">