Как решить неравенства?
(3√3)^[x]≥√3 3^[1/2*x+1]≥3^[1/2] 1/2*x+1≥1/2 x+2≥1 x≥-1 (4∛4)^[x]≤∛4 4^[1/3*x+1]≤4^[1/3] 1/3*x+1≤1/3 x+3≤1 x≤-2