Пределы срочно lim(x^3-4x+1) x->бесконечности lim x/корень x+1 - 1 x->0
!) limx-->≈(x^3-4x+1) = limx-->≈[(x^3)/(x^3) - (4x)/(x^3) + 1/(x^3)] = 1 2) limx->0 x/[√(x+1) - 1] = limx->0 x*[√(x+1) + 1]/[√(x+1) - 1]*[√(x+1) + 1] = = limx->0 x*[√(x+1) + 1]/[x+1 - 1] = limx->0 x*[√(x+1) + 1]/[x] = 2