Решите систему уравнений 3х - ху = 10 у + ху = 6
3x - xy = 10 y + xy = 6 x(3-y) = 10 y+xy = 6 x = 10/(3-y) y + 10y/(3-y) = 6 y(3-y) + 10y = 6(3-y) 3y - y2 + 10y = 18 - 6y y2 - 6y - 13y + 18 = 0 y2 - 19y + 18 = 0 y1 = 18 y2 = 1 x1: 18 + 18x = 6 3 + 3x = 1 x = -2 / 3 x2: 1 + x = 6 x = 5