8х^2-16х+7=0 можете помочь? )
8x^2 - 16x + 7 = 0 D = (-16)^2 - 4*8*7 = 256 - 224 = 32 √D = √(16*2) = 4√2 x1 = ( 16 + 4√2)/16 = (4 + √2)/4 x2 = ( 4 - √2)/4 = 1 - √2/4 Ответ: x = 1 ± √2/4