Решите уравнение lg(7x+1)=lg(2x-6)

Lg(7x + 1) = lg(2x-6) < br> ОДЗ:
0 } \atop {2x -6 > 0}} \right. " alt=" \left \{ {{7x + 1 > 0 } \atop {2x -6 > 0}} \right. " align="absmiddle" class="latex-formula"> < /br>
-1/7 } \atop {x>3}} \right. " alt=" \left \{ {{x > -1/7 } \atop {x>3}} \right. " align="absmiddle" class="latex-formula">
x ∈ (3; +∞)
lg(7x+1) - lg(2x-6) = 0

lg $\frac{(7x+1)}{(2x-6)}$ = 0

$\frac{(7x+1)}{(2x-6)}$ = 10°

$\frac{(7x+1)}{(2x-6)}$ = 1

5x = -7
x = -1,4
-1,4 не входит в ОДЗ => нет корней.