Помогите прошуу! только а) и б)

$1 \frac{2}{3} x+ \frac{5}{6}x =2 \frac{1}{2} + \frac{7}{12} -4 \frac{1}{4}$
$1 \frac{4}{6} x+ \frac{5}{6} x=2 \frac{6}{12} + \frac{7}{12} -4 \frac{3}{12}$
$2 \frac{1}{2} x=-1 \frac{1}{6}$
$x=- \frac{7}{6} * \frac{2}{5}$
$x=- \frac{7}{15}$
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$1 \frac{3}{5} y-2 \frac{4}{15}y= \frac{1}{10}-3 \frac{11}{30} +1 \frac{7}{15}$
$1 \frac{9}{15} y-2 \frac{4}{15} y= \frac{3}{30} -3 \frac{11}{30}+1 \frac{14}{15}$
$- \frac{2}{3} y=-2 \frac{2}{5}$
$y=- \frac{12}{5} *(- \frac{3}{2} )$
$y= \frac{18}{5} =3 \frac{3}{5}$