Y=e^(1/(x+5))/(x+5)^2 найти производную

Решите задачу:

$y=\frac{e^{\frac1{x+5}}}{(x+5)^2}\\y'=\frac{\left(e^{\frac1{x+5}}\right)'\cdot(x+5)^2-e^{\frac1{x+5}}\cdot\left((x+5)^2\right)'}{(x+5)^4}=\\=\frac{e^{\frac1{1+5}}\cdot\left(\frac1{x+5}\right)'\cdot(x+5)^2-e^{\frac1{x+5}}(2x+10)}{(x+5)^4}=\\=\frac{e^{\frac1{x+5}\cdot\left(-\frac1{(x+5)^2}\cdot(x+5)^2-(2x+10)\right)}}{(x+5)^4}=-\frac{e^{\frac1{x+5}}\cdot\left(1+2x+10\right)}{(x+5)^4}=-e^{\frac1{x+5}}\cdot\frac{2x+11}{(x+5)^4}$