(8x+1)(2xx-3)-1=(4x-2)² x⁴-26x²+25=0 4x³-x²=0 (x⅔-5)²-3(x²-5)-4=0 x³-4x² и 9x-36

Question

(8x+1)(2xx-3)-1=(4x-2)²
x⁴-26x²+25=0
4x³-x²=0
(x⅔-5)²-3(x²-5)-4=0
x³-4x² и 9x-36

Answer 1

X(x^2-9)-4(x^2-9)=0

(x^2-9)(x-4)=0

x=-3    x=3    x=4