2*(x+0.5)^{2} \\4 x^{2} -1>2( x^{2} +0.25+x)\\4 x^{2} -1>2 x^{2} +0.5+2x\\4 x^{2} -1-2 x^{2} -0.5-2x>0\\2 x^{2} -2x-1.5>0\\2 x^{2} -2x-1.5=0 \\ D=4+12=16\\ \sqrt{D} =4\\ x_{1} = \frac{2+4}{4} = \frac{6}{4} =1.5\\ x_{2} = \frac{2-4}{4} = \frac{-2}{4} =-0.5\\2 x^{2} -2x-1.5=2(x+0.5)(x-1.5) " alt="(2x+1)(2x-1)>2*(x+0.5)^{2} \\4 x^{2} -1>2( x^{2} +0.25+x)\\4 x^{2} -1>2 x^{2} +0.5+2x\\4 x^{2} -1-2 x^{2} -0.5-2x>0\\2 x^{2} -2x-1.5>0\\2 x^{2} -2x-1.5=0 \\ D=4+12=16\\ \sqrt{D} =4\\ x_{1} = \frac{2+4}{4} = \frac{6}{4} =1.5\\ x_{2} = \frac{2-4}{4} = \frac{-2}{4} =-0.5\\2 x^{2} -2x-1.5=2(x+0.5)(x-1.5) " align="absmiddle" class="latex-formula">
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-0.5 1.5 x
x∈
Ответ: x∈ 