3\\7)log_{0.15}(5x-2)>log_{0.15}13\\8)log_{\frac{1}{9}}(x^2-5x+3)<9\\9)log_{0.01}(3x)+log_{0.01}(\frac{x}{3})\geq log_{0.1}77\\10)11^{log_11(x^2+8x+32)}\leq16" alt="1)log_2x=3\\2)log_4(2x+3)=\frac{1}{2}log_243\\3)7^{log_75x}=25\\4)\frac{log_37x}{log_34}=2\\5)log_7(2x^2)-log_7x=\frac{1}{log_82}\\6)log_5x>3\\7)log_{0.15}(5x-2)>log_{0.15}13\\8)log_{\frac{1}{9}}(x^2-5x+3)<9\\9)log_{0.01}(3x)+log_{0.01}(\frac{x}{3})\geq log_{0.1}77\\10)11^{log_11(x^2+8x+32)}\leq16" align="absmiddle" class="latex-formula">