0\\6a-\frac{9}{a}+3=0|*\frac{a}{3}\\2a^2-3+a=0\\2a^2+a-3=0\\a_{1,2}=\frac{-1^+_-5}{4}\\a_1=-\frac{3}{2}; \ a_2=1\\.\ \ \ \ \ \ \ \ \ \ \ \ \frac{5}{6}^x=1\\.\ \ \ \ \ \ \ \ \ \ \ \ \ x=0" alt="5*(\frac{5}{6})^{x-1}-9*\frac{6}{5}^x+3=0\\6*\frac{5}{6}^x-9*\frac{6}{5}^x+3=0;\frac{5}{6}^x=a;a>0\\6a-\frac{9}{a}+3=0|*\frac{a}{3}\\2a^2-3+a=0\\2a^2+a-3=0\\a_{1,2}=\frac{-1^+_-5}{4}\\a_1=-\frac{3}{2}; \ a_2=1\\.\ \ \ \ \ \ \ \ \ \ \ \ \frac{5}{6}^x=1\\.\ \ \ \ \ \ \ \ \ \ \ \ \ x=0" align="absmiddle" class="latex-formula">