CaC2+2HCl=CaCl2+C2H2
1)CH4+2O2=CO2+2H2O
2)2C2H2+5O2=4CO2+2H2O
n(O2)=123,2:22,4=5,5моль;
n(O2)2)=(5,5:7)*5=3,93моль; n(C2H2)=(3,93*2):5=1,572моль; n(CaC2)=1,572моль;
m(CaC2)=1,572*64=100,608г; W(CaC2)=100.608:154=0,65(65%).
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