2^[3x+2]-2^[3x-2]=30
2^[2] * 2^[3x] - 2^[-2] * 2^[3x] =30
4*2^[3x] - 1/4*2^[3x]=30 |*4
16*2^[3x]-2^[3x]=30*4
15*2^[3x]=30*4
2^[3x]=8
2^[3x]=2^[3]
3x=3
x=1
Ответ: 1.
3^[x-1]-3^[x]+3^[x+1]=63
3^[-1]*3^[x]-3^[x]+3^[x]*3^[1]=63
1/3*3^[x] -3^[x] +3*3^[x]=63 |*3
3^[x]-3*3^[x]+9*3^[x]=63*3
7*3^[x] = 63*3
3^[x] = 9*3
3^[x] = 3^3
x=3
Ответ: 3.