решите неравенства: -2x^2+10x-12<0 2x^2+2>0 x^2+2x+3<0 3x>x^2

Question

решите неравенства:

-2x^2+10x-12<</u>0

2x^2+2>0

x^2+2x+3<</u>0

3x>x^2

Answer 1

===================================================

Answer 2

1)-2x^2+10x-12=0

D=(10)^2-4*(-2)*-(12)=100-96=4

x1=-10+2/4=-2

x2=-10-2/4=-3