Помогите пожалуйста решить!
sin (5x - )\frac{\pi}{2} = \frac{1}{2}" alt="2 cos x = \sqrt{2}
sin (5x - )\frac{\pi}{2} = \frac{1}{2}" align="absmiddle" class="latex-formula">
1)2cosx = √2
cos x = √2/2
x = π/4
2)sin(5x-π/2) = 1/2
5x - π/2 = π/6
5x = 2π/3
x = 2π/15
3)tg 3x = 1
3x = π/4
x = π/12
