(x-2)^2=(x+3)^2 решите уравнение
По формуле a^2 - b^2 = (a - b)* (a + b) (x-2)^2 - (x+3)^2 = 0 (x - 2 - (x + 3)) * (x - 2 + x + 3) = 0 (x- 2 - x - 3) * ( x - 2 + x + 3)= 0 - 6* (2x + 1) = 0 2x = - 1 x = - 1/2 = - 0 .5