Вычислите: 1) (29-6 5/8)-(4-5/7) = 2) (46 2/9-25)-(11 4/7-2/3)=

Решите задачу:

$1) (29-6 \frac{5}{8} )-(4- \frac{5}{7} )=(28 \frac{8}{8} -6 \frac{5}{8} )-(3 \frac{7}{7} - \frac{5}{7} )= \\ \\ =22 \frac{3}{8} -3 \frac{2}{7} =22 \frac{21}{56}-3 \frac{16}{56} =19 \frac{5}{56}$

$2)(46 \frac{2}{9} -25)-(11 \frac{4}{7} - \frac{2}{3} )=21 \frac{2}{9} -(11 \frac{12}{21} - \frac{14}{21} )= \\ \\ =21 \frac{2}{9} -(10 \frac{33}{21} - \frac{14}{21} )=21 \frac{2}{9} -10 \frac{19}{21} =21 \frac{14}{63} -10 \frac{57}{63} = \\ \\ =20 \frac{80-57}{63} =20 \frac{23}{63}$