Нет фотика(((
1) = log(3)125+ log(3)1/45 - 2/log(5)3 = log(3)125*1/45 - 2*log(3)5 = log(3)5^2/3^2 - 2* log(3)5 = 2*log(3)5/3 - 2*log(3)5 = 2*log(3) 5 - 2*log(3)5 = 0
3) = (log(1/3)X )^2 + 2* log(1/3)X - 3 = 0
теор виета
log(1/3)X = -3 не подходит >0 должно быть
log (1/3)X = 1 =>> X=1/3