Cos² x=1/2
cos² x - 1/2=0
(cos x- 1) (cosx + 1 ) =0
√2 √2
cos x - 1 =0 cos x + 1 =0
√2 √2
cos x= 1 cos x = - 1
√2 √2
x=+ arccos 1 +2πn x=+ arccos (- 1) + 2πn
√2 √2
x=+ π + 2πn x=(+/-)(π - arccos( 1)) + 2πn
4 √2
x=(+/-)(π - π )+2πn
4
x=(+/-)3π + 2πn
4
Ответ: х₁=(+/-) π +2πn
4
x₂=(+/-) 3π +2πn
4