2sin x+√2 ------------ =0 2cos x-√2

Question

2sin x+√2

------------ =0

2cos x-√2

Answer 1

одз: 2 cosx - ^2 ne ravno 0

2 cosx=/=^2 I:2

cosx =/= ^2/2

x=/=arccos^2/2 + 2Пn; nez

x=/= П/4+2 П  n

 

 

 

reshenie:

2 sin x +^2 =0

2 sinx=-^2 I:2

sinx=-^2/2

 

 x=(-1)^{k}arcsin(- П/4)+ Пk; kez