0;\\ sin 3x+sin 3x-\sqrt{3}>0;\\ 2sin 3x-\sqrt{3}>0;\\ sin (3x)>\frac{\sqrt{3}}{2};\\ \frac{\pi}{3}+2* \pi*k < 3x< \frac{2 \pi}{3}+2*\pi*k;\\ \frac{\pi}{9}+\frac{2* \pi*k}{3}0;\\ sin 3x+sin 3x-\sqrt{3}>0;\\ 2sin 3x-\sqrt{3}>0;\\ sin (3x)>\frac{\sqrt{3}}{2};\\ \frac{\pi}{3}+2* \pi*k < 3x< \frac{2 \pi}{3}+2*\pi*k;\\ \frac{\pi}{9}+\frac{2* \pi*k}{3}
ответ: x є ![\frac{\pi}{9}+\frac{2* \pi*k}{3}<x \frac{2\pi}{9}+\frac{2* \pi*k}{3} \frac{\pi}{9}+\frac{2* \pi*k}{3}<x \frac{2\pi}{9}+\frac{2* \pi*k}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%7D%7B9%7D%2B%5Cfrac%7B2%2A+%5Cpi%2Ak%7D%7B3%7D%3Cx+%5Cfrac%7B2%5Cpi%7D%7B9%7D%2B%5Cfrac%7B2%2A+%5Cpi%2Ak%7D%7B3%7D+)