Решите задачу:
ОДЗ: 0 } \atop {5x-12>0}} \right. " alt=" \left \{ {{ x^{2}-3x>0 } \atop {5x-12>0}} \right. " align="absmiddle" class="latex-formula"> Решение: x²-3x=5x-12 x²-8x+12=0 (x-6)(x-2)=0 x₁=6 x₂=2 - не подходит ОДЗ Ответ: x=6
0 } \atop {5x-12>0}} \right. " alt=" \left \{ {{ x^{2}-3x>0 } \atop {5x-12>0}} \right. " align="absmiddle" class="latex-formula">