ПОМОГИТЕ РЕШИТЬ ПОЖАЛУЙСТА! ДАЮ МНОГО БАЛЛОВ Решите систему уравнений (5х+3)^2=8у...

$\left \{ {{(5x+3)^2=8y} \atop {(3x+5)^2=8y}} \right.$
$\left \{ {{(5x+3)^2=8y} \atop {(3x+5)^2=(5x+3)^2}} \right.$
$\left \{ {{(5x+3)^2=8y} \atop {(3x+5)^2-(5x+3)^2=0}} \right.$
$\left \{ {{(5x+3)^2=8y} \atop {(3x+5-5x-3)(3x+5+5x+3)=0}} \right.$
$\left \{ {{(5x+3)^2=8y} \atop {(2-2x)(8x+8)=0}} \right.$
$(2-2x)(8x+8)=0$
$2-2x=0$ или    $8x+8=0$
$x=1$    или    $x=-1$
$\left \{ {{x=1} \atop {(5*1+3)^2=8y}} \right.$ или    $\left \{ {{x=-1} \atop {(5*(-1)+3)^2=8y}} \right.$
$\left \{ {{x=1} \atop {8y=64}} \right.$ или    $\left \{ {{x=-1} \atop {8y=4}} \right.$
$\left \{ {{x=1} \atop {y=8}} \right.$    или $\left \{ {{x=-1} \atop {y=0,5}} \right.$

Ответ: (1;8); (-1; 0,5)