9 целых 13\19 + (8 целых 18\19 - 3 целых 15\19)=??? 10 целых 4\21 - (4 целых 10\21+3...

Решите задачу:

$9 \frac{13}{19} + (8 \frac{18}{19} - 3 \frac{15}{19} ) = 9 \frac{13}{19} + 5 \frac{3}{19} = 14 \frac{16}{19}$

$10 \frac{4}{21} - ( 4 \frac{10}{21} + 3 \frac{19}{21} ) = 10 \frac{4}{21} - 7 \frac{29}{21} = 8 \frac{46}{21} - 7 \frac{29}{21} = 1 \frac{17}{21}$