(x+5)^2+(x-2)^2+(x-7)(x+7)=11x+80

Question

(x+5)^2+(x-2)^2+(x-7)(x+7)=11x+80

Answer 1

X²+10x+25+x²-4x+4+x²-49=11x+80
3x²+6x-20-11x+80=0
3x²-5x-100=0
d=25+1200=1225
x1=

Comments

x1=(5+35)/6=40/6=6 целю 2/3

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x2=(5-35)/6=-30/6=-5