извлеките корни: 1) 4√700-27√7= 2)√75-6√3= 3)2√50-8√2= 4)5√12-7√3= 5)3√72-4√2+2√98=...

Решите задачу:

$1)4 \sqrt{700} - 27 \sqrt{7} = 4 \sqrt{100*7} - 27 \sqrt{7} =40 \sqrt{7} - 27 \sqrt{7} = 13 \sqrt{7}$
$\sqrt{75} - 6 \sqrt{3} = \sqrt{25*3} - 6 \sqrt{3} = 5 \sqrt{3} - 6 \sqrt{3} = - \sqrt{3}$
$3) 2 \sqrt{50} - 8 \sqrt{2} = 2 \sqrt{25*2} - 8 \sqrt{2} = 10 \sqrt{2} - 8 \sqrt{2} = 2 \sqrt{2}$
$4) 5 \sqrt{12} -7 \sqrt{3} = 5 \sqrt{4*3} - 7\sqrt{3} =10 \sqrt{3} - 7 \sqrt{3} = 3 \sqrt{3}$
$6) \frac{1}{3} \sqrt{108} + \sqrt{363} - \frac{2}{9} \sqrt{243}=$
$\frac{1}{3} \sqrt{36*3} + \sqrt{121*3} - \frac{2}{9} \sqrt{81*3}=$
$\frac{1}{3}*6 \sqrt{3} + 11 \sqrt{3} - \frac{2}{9}*9 \sqrt{3}= 2 \sqrt{3} + 11 \sqrt{3}- 2 \sqrt{3}= 11 \sqrt{3}$