Пятое срочно!!!!!!!!!!!!
негусто с помощниками )))
1) ОДЗ 2/(a-1) + (a-2)/(a-3)≥2 (2a-6+a²-2a-a+2)/(a-1)(a-3) -2≥0 (a²-a-4-2a²+8a-6)/(a-1)(a-3)≥0 (a²-7a+10)/(a-1)(a-3)≤0 a1+a2=7 U a1*a2=10⇒a1=2 U a2=5 a=1 U a=3 + _ + _ + -------------------------------------------------------------------- 1 2 3 5 11<5^(x+1)≤2⇒0<x+1≤log(5)2⇒-1<x≤-1+log(5)2<br>3<5^(x+1)≤5⇒log(5)3<x+1≤1⇒-1+log(5)3<x≤0<br>x∈(-1;-1+log(5)2] U (-1+log(5)3;0] 2)[2/(25x²+40x+7) +(25x²+40x+4)/2]²≥4 (25x²+40x+7)/2=b (1/b +b)²≥4 (1/b +b -2)(1/b +b -2)≥0 (b²-2b+1)/b *(b²+2b+1)/b≥0 (b-1)²(b+1)²/b²≥0 b<0 U b>0⇒b≠0 25x²+40x+7≠0 D=1600-700=900 x1=(-40-30)/50=-1,4 U x2=(-40+30)/50=-0,2 x∈(-∞;-1,4) U (-1,4;-0.2) U (-0,2;∞) Ответ x∈(-1;-1+log(5)2] U (-1+log(5)3;-0,2) (-0,2;0]