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Решите задачу:

$(\frac {7}{330} + \frac{2}{495}): \frac{5}{11} =(\frac {7}{330} + \frac{2}{495})* \frac{11}{5} = \\ \\ =\frac {7}{330}* \frac{11}{5} + \frac{2}{495}* \frac{11}{5} =\frac {7}{30}* \frac{1}{5} + \frac{2}{45}* \frac{1}{5} =(\frac {7}{30} + \frac{2}{45})* \frac{1}{5} = \\ \\ =(\frac {21}{90} + \frac{4}{90})* \frac{1}{5} =\frac {25}{90}* \frac{1}{5} =\frac {5}{90}* \frac{1}{1} =1/18$