(x^5)`= (√x)`= (2x^10-x^8+3x^3)`=

Question

(x^5)`=

(√x)`=

(2x^10-x^8+3x^3)`=

Answer 1

(x⁵)'=5*x⁴
(√x)'=(x^(1/2))'=(1/2)*x^(-1/2)=0,5/√x
(2x¹⁰-x⁸+3x³)'=20x⁹-8x⁷+9x²