Одним словом пож помащ нужна номер 695

Решите задачу:

$(1\frac{1}{12}+1\frac{1}{4})*1\frac{19}{56}+2\frac{5}{8}*1\frac{3}{7}*1\frac{1}{9} =(\frac{13}{12}+\frac{5}{4})* \frac{75}{56}+\frac{21}{8}*\frac{10}{7}*\frac{10}{9}=$ $(\frac{13}{12}+\frac{5*3}{4*3})* \frac{75}{56}+\frac{7*3}{2*4}*\frac{2*5}{7}*\frac{2*5}{3*3}=\frac{13+15}{12}*\frac{75}{56}+\frac{25}{6}=\frac{28}{12}*\frac{75}{56}+\frac{25}{6}=$ $\frac{2*14}{3*4}*\frac{75}{4*14}+\frac{25}{6} =\frac{25}{8}+\frac{25}{6}= \frac{25*3+25*4}{24} = \frac{75+100}{24}= \frac{175}{24}=7 \frac{7}{24}$