2(5x+4)-5*(2x+4)>4x
(x-1)(x+4)<0<br>==
Решаем неравенство
(x-1)(x+4)<0<br>x_1 = 1
x_2 = -4
==
Методом интервалов.
+ -4 - 1 +
----------------------------- ----------------------------- ----------------------->
x∈(-4;1)
==
Решаем неравенство
2(5x+4)-5*(2x+4)>4x
10x + 8 - 10x - 20 > 4x
-12>4x
-12-4x>0
-4x>12
x<-3<br> \\\\\\\\\\\\\\\\\\\\\ -3
---------------------------- ----------------------------->
x∈(-∞;-3)
==
\\\\\\\\\\\\\\\\ -4 \\\\\\\-3 1
------------------ -------------------- ------------>
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x∈(-4;-3)
Ответ: x∈(-4;-3)