Помогите пожалуйста, не понимаю это тему!
а) Знаменатель нужно привести к виду
б) Знаменатель нужно привести к виду
в) Знаменатель нужно привести к виду
![\sqrt[n]{a^n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5En%7D "\sqrt[n]{a^n}")
![\frac{5}{\sqrt[3]{4}}=\frac{5}{\sqrt[3]{2^2}}=\frac{5\sqrt[3]2}{\sqrt[3]{2^2}\cdot\sqrt[3]2}=\frac{5\sqrt[3]2}{\sqrt[3]{2^2\cdot2}}=\frac{5\sqrt[3]2}{\sqrt[3]{2^3}}=\frac{5\sqrt[3]2}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B%5Csqrt%5B3%5D%7B4%7D%7D%3D%5Cfrac%7B5%7D%7B%5Csqrt%5B3%5D%7B2%5E2%7D%7D%3D%5Cfrac%7B5%5Csqrt%5B3%5D2%7D%7B%5Csqrt%5B3%5D%7B2%5E2%7D%5Ccdot%5Csqrt%5B3%5D2%7D%3D%5Cfrac%7B5%5Csqrt%5B3%5D2%7D%7B%5Csqrt%5B3%5D%7B2%5E2%5Ccdot2%7D%7D%3D%5Cfrac%7B5%5Csqrt%5B3%5D2%7D%7B%5Csqrt%5B3%5D%7B2%5E3%7D%7D%3D%5Cfrac%7B5%5Csqrt%5B3%5D2%7D%7B2%7D "\frac{5}{\sqrt[3]{4}}=\frac{5}{\sqrt[3]{2^2}}=\frac{5\sqrt[3]2}{\sqrt[3]{2^2}\cdot\sqrt[3]2}=\frac{5\sqrt[3]2}{\sqrt[3]{2^2\cdot2}}=\frac{5\sqrt[3]2}{\sqrt[3]{2^3}}=\frac{5\sqrt[3]2}{2}")
![(\sqrt[3]{a}+b)(\sqrt[3]{a^2}-b\sqrt[3]{a}+b^2)](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7Ba%7D%2Bb%29%28%5Csqrt%5B3%5D%7Ba%5E2%7D-b%5Csqrt%5B3%5D%7Ba%7D%2Bb%5E2%29 "(\sqrt[3]{a}+b)(\sqrt[3]{a^2}-b\sqrt[3]{a}+b^2)")
![\frac{\sqrt[3]6}{\sqrt[3]6+1}=\frac{\sqrt[3]6(\sqrt[3]{6^2}-\sqrt[3]6+1)}{(\sqrt[3]6+1)(\sqrt[3]{6^2}-\sqrt[3]6+1)}=\frac{\sqrt[3]6\sqrt[3]{6^2}-\sqrt[3]6\sqrt[3]6+\sqrt[3]6}{(\sqrt[3]6)^3+1^3}= \\ \frac{6-\sqrt[3]{6^2}+\sqrt[3]6}{6+1}=\frac{6-\sqrt[3]{6^2}+\sqrt[3]6}{6}=](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D6%7D%7B%5Csqrt%5B3%5D6%2B1%7D%3D%5Cfrac%7B%5Csqrt%5B3%5D6%28%5Csqrt%5B3%5D%7B6%5E2%7D-%5Csqrt%5B3%5D6%2B1%29%7D%7B%28%5Csqrt%5B3%5D6%2B1%29%28%5Csqrt%5B3%5D%7B6%5E2%7D-%5Csqrt%5B3%5D6%2B1%29%7D%3D%5Cfrac%7B%5Csqrt%5B3%5D6%5Csqrt%5B3%5D%7B6%5E2%7D-%5Csqrt%5B3%5D6%5Csqrt%5B3%5D6%2B%5Csqrt%5B3%5D6%7D%7B%28%5Csqrt%5B3%5D6%29%5E3%2B1%5E3%7D%3D+%5C%5C+%5Cfrac%7B6-%5Csqrt%5B3%5D%7B6%5E2%7D%2B%5Csqrt%5B3%5D6%7D%7B6%2B1%7D%3D%5Cfrac%7B6-%5Csqrt%5B3%5D%7B6%5E2%7D%2B%5Csqrt%5B3%5D6%7D%7B6%7D%3D "\frac{\sqrt[3]6}{\sqrt[3]6+1}=\frac{\sqrt[3]6(\sqrt[3]{6^2}-\sqrt[3]6+1)}{(\sqrt[3]6+1)(\sqrt[3]{6^2}-\sqrt[3]6+1)}=\frac{\sqrt[3]6\sqrt[3]{6^2}-\sqrt[3]6\sqrt[3]6+\sqrt[3]6}{(\sqrt[3]6)^3+1^3}= \\ \frac{6-\sqrt[3]{6^2}+\sqrt[3]6}{6+1}=\frac{6-\sqrt[3]{6^2}+\sqrt[3]6}{6}=")
![(\sqrt[3]{a}-b)(\sqrt[3]{a^2}+b\sqrt[3]{a}+b^2)](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7Ba%7D-b%29%28%5Csqrt%5B3%5D%7Ba%5E2%7D%2Bb%5Csqrt%5B3%5D%7Ba%7D%2Bb%5E2%29 "(\sqrt[3]{a}-b)(\sqrt[3]{a^2}+b\sqrt[3]{a}+b^2)")