Решите уравнение: cos^2 x(x+pi/3)=1
Sin²(x + π/3) = 1 1) sin(x + π/3) = - 1 x + π/3 = - π/2 + 2πk, k ∈z x = - π/3 - π/2 + 2πk, k ∈z x = - 5π/6 + 2πk, k ∈z 2) sin(x + π/3) = 1 x + π/3 = π/2 + 2πn, n∈Z x= - π/3 + π/2 + 2πn, n∈Z x= π/6 + 2πn, n∈Z
cos²(x + π/3) = 1 1) cos(x + π/3) = - 1 x + π/3 = π + 2πk, k ∈z x = - π/3 + π + 2πk, k ∈z x = 2π/3 + 2πk, k ∈z 2) cos(x + π/3) = 1 x + π/3 = 2πn, n∈Z x= - π/3 + 2πn, n∈Z
Cos²(x+π/3)=1 [1+cos(2x+2π/3)]/2=1 1+cos(2x+2π/3)=2 cos(2x+2π/3)=1 2x+2π/3=2πn 2x=-2π/3+2πn x=-π/3+πn