6x(3y+1)-8∙(3y+1)=(3y+1)(6x-8),якщо x= 1 2/3, y=0,4

Question

6x(3y+1)-8∙(3y+1)=(3y+1)(6x-8),якщо x= 1 2/3, y=0,4

Answer 1

18xy+6x-24y-8=18yx-24y+6x-8=18xy+6x-24y-18yx-24y+6x-8+8=12x-48y=12 *1 2/3-48 * 0,4=12/1 * 5/3 - 19,2= 20-19,2=0,8