а) 5√2 + 23√27 - √98 б) (4√3 + √27) √3 в) ( √5- √3)во второй степени.

Question

а) 5√2 + 23√27 - √98 б) (4√3 + √27) √3 в) ( √5- √3)во второй степени.

Answer 1

(\sqrt{5}-\sqrt{3})^2=5-2\sqrt{15}+3=8-2\sqrt{15}=2(4-\sqrt{15})" alt="5\sqrt{2}+23\sqrt{27}-\sqrt{98}=6\sqrt{2}+69\sqrt{3}-7\sqrt{2}=69\sqrt{3}-\sqrt{2} 4\sqrt{3}+\sqrt{27}=4\sqrt{3}+3\sqrt{3}=7\sqrt{3}

(\sqrt{5}-\sqrt{3})^2=5-2\sqrt{15}+3=8-2\sqrt{15}=2(4-\sqrt{15})" align="absmiddle" class="latex-formula">

Answer 2

а)5√2+23√27-√98=5√2+69√3-7√2=-2√2+69√3

б)4√3*√3+√27*√3=√144+√81=√225=15

в)(√5-√3)^2=(√5)^2-2*√5*√3+(√3)^2=5-2√15+3=8-2√15=2(4-√15)