0} \atop {x-1>0}} \right. ,\; x>1\\\\log(x+3)+log_5(x-1)=1,\; \; 1=log_55\\\\(x+3)(x-1)=5\\\\x^2+2x-8=0\\\\x_1=-4<1,\; x_2=2\\\\Otvet:\; x=2." alt="log_5(x+3)=1-log_5(x-1)\; ,\; \; ODZ:\; \left \{ {{x+3>0} \atop {x-1>0}} \right. ,\; x>1\\\\log(x+3)+log_5(x-1)=1,\; \; 1=log_55\\\\(x+3)(x-1)=5\\\\x^2+2x-8=0\\\\x_1=-4<1,\; x_2=2\\\\Otvet:\; x=2." align="absmiddle" class="latex-formula">