sin(4 arccos(-1/2)-2 arctan sqrt 3/3) 5arccos 1/2 +3arcsin(-sqrt2/2)

Question

sin(4 arccos(-1/2)-2 arctan sqrt 3/3)

5arccos 1/2 +3arcsin(-sqrt2/2)

Answer 1

1) sin(4*(-п/3)-2*п/6)=sin(-8п/6-2п/6)=sin2п=0