2)2\5√(150b)-0/2√(7.26b)+11√(0.54b)=2\5√(25·6b)-0.2√(1.21·6b)+11√(0.09·6b)=2\5·5√(6b)-0.2·1.1√(6b)+11·0.3√(6b)=2√(6b)-0.22√(6b)+3.3√(6b)=5.08√(6b)
3) 0.4√(0.28y)+5√(252y)-1.2√(175y)=0.4√(7y·0.04)+5√(7y·36)-1.2√(7y·25)=0.4·0.2√(7y)+
+5·6√(7y)-1.2·5√(7y)=0.08√(7y)+30√(7y)-6√(7y)=23.92√(7y)
4) 3\7√(539c)-0.6√(1100c)+√(0.99c)=3\7√(49·11c)-0.6√(100·11c)+√(0.09·11c)=3\7·7√(11c)-
-0.6·10√(11c)+0.3√(11c)=3√(11c)-6√(11c)+0.3√(11c)=-2.7√(11c)