√(x+5) + √(6-5x-x²)
{x+5≥0
{6-5x-x²≥0
x+5≥0
x≥-5
6-5x-x²≥0
x²+5x-6≤0
x²+5x-6=0
D=25+24=49
x₁=-5-7=-6
2
x₂=-5+7=1
2
+ - +
------- -6 ------------ 1 ------------
\\\\\\\\\\\\\\
x∈[-6; 1]
{x≥-5
{-6≤x≤1
\\\\\\\\\\\\\\\\\\\\\\\\\\\\
-------- -6 ------- -5 ----------- 1 ---------
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
x∈[-5; 1]