помогите плииз решить уравнение1) y-5/6=4/3 2) 5/6=15/2х-3 3)2/5= 6/х+3 4) 12:4/5х=20:1/4

Решите задачу:

$1)y- \frac{5}{6} = \frac{4}{3} \\ y= \frac{4}{3} + \frac{5}{6} \\ y= \frac{8}{6} + \frac{5}{6} \\ y= \frac{13}{6} = 2\frac{1}{6} \\ \\ 2) \frac{5}{6} = \frac{15}{2}x -3 \\ 3+ \frac{5}{6} = \frac{15}{2}x \\ 3\frac{5}{6} = \frac{15}{2}x \\ \frac{18+5}{6} = \frac{15}{2}x \\ \frac{18}{6} : \frac{15}{2}=x \\ \frac{18}{6} *\frac{2}{15}=x \\ \frac{2}{3}=x \\$
$3) \frac{2}{5} = \frac{6}{x} +3 \\ \frac{2}{5}-3=\frac{6}{x} \\ \frac{2-15}{5}=\frac{6}{x} \\ \frac{2-15}{5}=\frac{6}{x} \\ -13x=30 \\ x=- \frac{13}{30}$

$4)12: \frac{4}{5} x=20: \frac{1}{4} \\ 12* \frac{5}{4} =20x* \frac{4}{1} \\ 15=80x \\ x= \frac{15}{80} \\ x= \frac{3}{16}$