Решить уравнение sin(4x-pi/3)=1/2

Question

Решить уравнение
sin(4x-pi/3)=1/2

Answer 1

4x-π/3=(-1)^narcsin1/2+πn
4x-π/3=(-1)^n(π/6)+πn, n∈Z
4x=(-1)^n(π/6)+π/3 +πn,
x=(-1)^n(π/24)+π/12+πn/4

Answer 2

Sin(4x-π/3)=1/2
4x-π/3=π/6+2π *n
4x-π/3=-π/6+2π*n
x₁=π/8+πn/2
x₂=π/24+πn/2

Comments

razve tak?

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да так =)

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posmatri moe reshenie ladno?

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=) и что?

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oni odinakovi?