Система (1/5)^5x-y=25 и (2)^2x-y=2^-5 решить систему

Решите задачу:

$\left \{ {{ (\frac{1}{5} )^{5x-y}=25} \atop {2^{2x-y}=2^{-5}}} \right. \left \{ {{ (5^{-1})^{5x-y}=5^2} \atop {2^{2x-y}=2^{-5}}} \right. \left \{ {{ 5^{-5x+y}=5^2} \atop {2^{2x-y}=2^{-5}}} \right. \left \{ {{-5x+y=2} \atop {2x-y=-5}} \right. \left \{ {{-3x=-3} \atop {2x-y=-5}} \right.$

$\left \{ {{x=1} \atop {2*1-y=-5}} \right. \left \{ {{x=1} \atop {-y=-7}} \right. \left \{ {{x=1} \atop {y=7}} \right.$