Решите по теореме крамера очень подробно.

Решите задачу:

$1)\; \; \left \{ {{2x-4y=14} \atop {4x+3y=-27}} \right. \\\\\Delta = \left|\begin{array}{cc}2&-4\\4&3\end{array}\right| =6+16=22\\\\\Delta _1= \left|\begin{array}{cc}14&-4\\-27&3\end{array}\right| =42-108=-66\\\\\Delta _2= \left[\begin{array}{cc}2&14\\4&-27\end{array}\right| =-54-56=-110\\\\x=\frac{-66}{22}=-3\; ;\; \; y=\frac{-110}{22}=-5\\\\\\2)\; \; \left \{ {{3x+5y=14} \atop {2x-4y=-20}} \right. \\\\ \Delta =\left|\begin{array}{cc}3&5\\2&-4\end{array}\right| =-12-10=-22$

$\Delta _1= \left|\begin{array}{cc}14&5\\-20&-4\end{array}\right| =-56+100=44\\\\\Delta _2= \left|\begin{array}{cc}3&14\\2&-20\end{array}\right| =-60-28=-88\\\\x=\frac{44}{-22}=-2\; ;\; \; y=\frac{-88}{-22}=4$