4m (в квад)-9m(в квад) ÷ 2am+3an ------------------------------------- M(в квад)n(в...

Решите задачу:

$\frac{ \frac{4m ^{2}-9n ^{2} }{2am+3an} }{ \frac{m ^{2} n ^{2} }{2mn} } = \frac{4m-6n}{amn} \\ \\ 1)\frac{4m ^{2} -9n ^{2} }{2am+3an} = \frac{(2m-3n)(2m+3n)}{a(2m+3n)} = \frac{2m-3n}{a} \\ \\ 2) \frac{2m-3n}{a} * \frac{2mn}{m ^{2} n ^{2} } = \frac{2m-3n}{a} * \frac{2}{mn} = \frac{4m-6n}{amn}$

$\frac{ \frac{4m ^{2}-9m ^{2} }{2am+3an} }{ \frac{m ^{2} n ^{2} }{2mn} } = - \frac{10m}{2amn+3an ^{2} } \\ \\ 1) \frac{4m ^{2} -9m ^{2} }{2am+3an} =- \frac{5m ^{2} }{a(2m+3n)} \\ \\ 2) \frac{m ^{2} n ^{2} }{2mn} = \frac{mn}{2} \\ \\ 3)- \frac{5m ^{2} }{a(2m+3n)} * \frac{2}{mn} =- \frac{5m*2}{an(2m+3n)} =- \frac{10m}{2amn+3an ^{2} }$