Решите уравнение sin2x - 2cosx = 0
sin2x-2cosx=0
2 sin x cos x - 2 cos x = 0
2 cos x (sin x - 1) = 0
cos x = 0 sin x = 1
x=π/2+πn,n∈Z x=π/2+2πn, n∈Z
Ответ. х=π/2+πn, n∈Z