Решите номер 6.Есть вложение.

$a_n\ \textgreater \ 6 \ (n\in N) \\\ \frac{53}{n+1} \ \textgreater \ 6 \\\ \frac{53-6(n+1)}{n+1} \ \textgreater \ 0 \\\ \frac{53-6n-6}{n+1} \ \textgreater \ 0 \\\ \frac{47-6n}{n+1} \ \textgreater \ 0 \\\ \frac{ \frac{47}{6} -n}{n+1} \ \textgreater \ 0 \\\ \frac{n-\frac{47}{6} }{n+1} \ \textless \ 0 \\\ n\in (-1; \frac{47}{6} ) \\\ n\in\{1; \ 2; \ 3; \ 4; \ 5; \ 6; \ 7\}$
Ответ: 7 членов